Calculate the internal energy change in each of the following cases : (i) A system absorbs 5 kJ of heat and does 1 kJ of work. (ii) 5 kJ of work is done on the system and 1 kJ of heat is given out by the system.

Calculate the internal energy change in each of the following cases :

1.	Calculate the internal energy change in each of the following cases : (i) A system absorbs 5 kJ of heat and does 1 kJ of work. (ii) 5 kJ of work is done on the system and 1 kJ of heat is given out by the system.
Answer» (i) Here q + 5 kJ and w = - 1 kJ `therefore` According to first law of thermodynamics, `Delta E=q+w=5+(-1)=4kJ` (ii) Here w = + 5kJ and q = - 1kJ `therefore` According to first law of thermodynamic `Delta E=q+w=-1+(+5)=4 kJ` i.e. the internal energy of the system increases by 4 by in each case.

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Calculate the internal energy change in each of the following cases : (i) A system absorbs 5 kJ of heat and does 1 kJ of work. (ii) 5 kJ of work is done on the system and 1 kJ of heat is given out by the system.

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