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Calculate the interval between two sound waves of frequencies 1000 Hz and 400 Hz. Express the interval on logarithmic scale and in centioctaves. [Hint absolute interval `= n_(1)//n_(2)` interval on log scale log `n_(1)//n_(2)`, interval in centioctaves `= (log n_(1)//n_(2))/(log 2) xx 100.`] |
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Answer» Correct Answer - 2.5, 0.3979, 132.2 |
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