1.

Calculate the kinetic energy of a gram molecule of argon at `127^(@)C`.

Answer» Temperature , `T = 127^(@)C= 273+127 = 400K, R=8.31J//mol K`
`K.E.` per gram molecule of argon = ` 3/2 R T = 3/2 xx 8.31 xx 400 = 4986J`


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