1.

Calculate the kinetic energy of a photoelectron (in eV) emitted on shining light of wavelength 6.2 × 10^-6 m on a metal surface. The work function of the metal is 0.1 eV.(a) 10 eV(b) 0.1 eV(c) 0.01 eV(d) 1000 eVI have been asked this question in my homework.I'd like to ask this question from Einstein’s Photoelectric Equation : Energy Quantum of Radiation topic in section Dual Nature of Radiation and Matter of Physics – Class 12

Answer»

Correct option is (b) 0.1 eV

Easy EXPLANATION: Kmax = \(( \FRAC {hc}{\lambda })\) – W0

Kmax = \( [ \frac {(6.6 \TIMES 10^{-34} \times 3 \times 10^8 )}{(6.2 \times 10^{-6} \times 1.6 \times 10^{-19}) }] \) – 0.1.

Kmax = 0.2 – 0.1

Kmax = 0.1 eV



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