Calculate the kinetic energy of rolling ring of mass 0.2 kg about an axis passing through its centre of mass and perpendicular to it, if centre of mass is moving with a velocity of 3 m/s.

Calculate the kinetic energy of rolling ring of mass 0.2 kg about an a

1.	Calculate the kinetic energy of rolling ring of mass 0.2 kg about an axis passing through its centre of mass and perpendicular to it, if centre of mass is moving with a velocity of 3 m/s.
Answer» `KE=(1)/(2)mv_(CM)^(2)(1+(K^(2))/(R^(2)))` Moment of inertia of the ring about an axis passing through its centre of mass `= MR^(2)` `:. K=1` (radius of gyration) `m=0.2 kg,v_(CM) = 3 m//s` `KE=(1)/(2)xx0.2xx9(1+1)=0.2xx9=1.8 "kgm"^(2)s^(-2)`.

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Calculate the kinetic energy of rolling ring of mass 0.2 kg about an axis passing through its centre of mass and perpendicular to it, if centre of mass is moving with a velocity of 3 m/s.

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