Calculate the lattice energy of the reaction `Li^(o+)(g) +CI^(Theta) (g) rarr LiCI(s)` from the following data: `Delta_("sub")H^(Theta)(Li) = 160.67 kJ mol^(-1), (1)/(2)D(CI_(2)) = 122.17 kJ mol^(-1) IP(Li) = 520.07 kJ mol^(-1),E_(A)(CI) = - 365.26 kJ mol^(-1)` and `Delta_(f)H^(Theta)(LiCI) =- 401.66 kJ mol^(-1)`

Calculate the lattice energy of the reaction `Li^(o+)(g) +CI^(Theta) (

1.	Calculate the lattice energy of the reaction `Li^(o+)(g) +CI^(Theta) (g) rarr LiCI(s)` from the following data: `Delta_("sub")H^(Theta)(Li) = 160.67 kJ mol^(-1), (1)/(2)D(CI_(2)) = 122.17 kJ mol^(-1) IP(Li) = 520.07 kJ mol^(-1),E_(A)(CI) = - 365.26 kJ mol^(-1)` and `Delta_(f)H^(Theta)(LiCI) =- 401.66 kJ mol^(-1)`
Answer» Applying the reaction `-Q = DeltaH^(Theta) +(1)/(2)D +IP -EA +U` and substituting the respective values. `-401.66 = 160.67 +122.17 +520.07 - 365.25 +U` `U =- 839.31 kJ mol^(-1)`

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