1.

Calculate the lattice formation enthalpy in kJ mol−1of LiF given thatEnthalpy of sublimation of lithium = 155.3 kJ mol−1Dissociation enthalpy of half mole of F2=75.3 kJIonization enthalpy of lithium =520 kJ mol−1Electron gain enthalpy of 1 mol of F(g) =−333 kJΔfHoverall=−594 kJ mol−1

Answer»

Calculate the lattice formation enthalpy in kJ mol−1of LiF given that

Enthalpy of sublimation of lithium = 155.3 kJ mol−1

Dissociation enthalpy of half mole of F2=75.3 kJ

Ionization enthalpy of lithium =520 kJ mol−1

Electron gain enthalpy of 1 mol of F(g) =−333 kJΔfHoverall=−594 kJ mol−1



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