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Calculate the magnetic field induction at the centre of a hydrogen atom caused by an electron moving along the first Bohrorbit. |
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Answer» The revolving is electron is equivalent to a circular current `I=(e )/(T)=(e )/(2pi r//v)=(ev)/(2pir)` The magnetic induction `B=(mu_(0)I)/(2r)=(mu_(0)ev)/(4pir^(2))=(mu_(0))/(4pi).e.(e^(2))/((4pi epsilon_(0)) ħ).[(me^(2))/( ħ^(2)(4pi epsilon_(0)))]^(2)` `=(mu_(0)m^(2)e^(7))/(256pi^(4)epsilon_(0)^(3) ħ^(5))` Substitution gives `B= 12.56T` ar the centre. (In Gaussian units `B=(m^(2)e^(7))/(c ħ^(5))= 125.6kG.`) |
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