1.

Calculate the mass of mercury which can be liberated from `HgO` at `25^(@)C` by the treatment of excess HgO with 41.84 kJ of heat at : (a) constant pressure (b) constant volume Given : `Delta H_(f)^(@)(HgO, s) = -90.8 kJ mol^(-1)` & `M(Hg) = 200.6 g mol^(-1)`.

Answer» Correct Answer - (a) 92.435 g (b) 93.715 g
(a) `HgO rarr Hg+1/2 O_(2) " "DeltaH=90.8`
For `41.84 kJ` heat, mass of `Hg=200.6/90.8 xx41.84=-92.435 g`
(b) Calculate at constant volume


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