Calculate the mass of the following: (i) 0.5moles of O_(2) gas(ii) 0.5moles of O atoms (iii) 3.011xx10^(23)"atoms of O"(iv) 6.022xx10^(23)"molecules of "O_(2) (Givem: Gram atomic mass of oxygen=16g) Gram of molecular mass of oxygen (O_(2))=32g)

Calculate the mass of the following: (i) 0.5moles of O_(2) gas(ii) 0.

1.	Calculate the mass of the following: (i) 0.5moles of O_(2) gas(ii) 0.5moles of O atoms (iii) 3.011xx10^(23)"atoms of O"(iv) 6.022xx10^(23)"molecules of "O_(2) (Givem: Gram atomic mass of oxygen=16g) Gram of molecular mass of oxygen (O_(2))=32g)
Answer» Solution :(i) 0.5 mole of `O_(2)` gas No. of moles`= ("Mass of "O_(2) " in grams")/("Gram molecular mass")= (m)/(M)` `therefore` Mass of `O_(2)` is gram (m) = No. of moles `xx M 0.5 xx (32G) = 16g` (ii) 0.5 moles of oxygen (O) atoms `"No. of gram atoms"=("Mass of oxygen (O) is grams")/("Gram atomic mass")=(m)/(M)` Mass of oxygen of (O) in grams (m) = No. OFMOLES `xx M = 0.5 xx (16g(0 = 8 g` (iii)`3.011 xx 10^(23)` atoms of oxgen (O) Step I : Calculationof no. of gram atoms of oxygen `"No.of gram atoms"=("No.of atoms of oxygen")/("Avogadro's no.of atoms")= (N)/(N_(0))` `= (3.011 xx 10^(23) )/(6.022xx 10^(23)) = 0.5` gram atom StepII :Calculation of mass of oxgyen (O) atoms Mass of oxygen (O) atoms =Gramatomic mass of oxygen `xx` No.ofgram atomsof oxygen `= (16g) xx 0.5 = 8 g` (iv) `6.022 xx 10^(23)` molecules of oxygen`(O_(2))` Step I: Calculation of no.of gram moles of oxygen. `"No.of gram moles"=("No.of atoms of oxygen")/("Avogadro's no.of atoms")= (N)/(N_(0))` `= (6.022 xx 10^(23))/(6.022 xx 10^(23)) = 1` gram mol. Step II: Calculationof mass of oxgyen`(O_(2))` molecules. Mass of oxygen `(O_(2))` molecules = Gram molecular mass of oxygen `xx` Noof grammoles of oxgyen `= (32 g) xx 1 = 23 g`.