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Calculate the maximum current in the circuit, if a capacitor of capacitance `1muF` is charged to a potential of 2 V and is connceted in parallel to an inductor of inductance `10^(-3)H`.A. `sqrt4000" "mA`B. `sqrt2000" "mA`C. `sqrt1000" "mA`D. `sqrt5000" "mA` |
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Answer» (a) charge on capacitor `q_(0)=CV" "q_(0)=2xx10^(-6)C` Here, `q=q_(0)sinomegat` For maximum current` =I_(0)=(dq)/(dt)=omegaq_(0)` `omega=(1)/(sqrtLC)=(10^(9))^(1//2),I_(0)=(10^(9))^(1//2)(2xx10^(-6))` `=sqrt10xx10^(4)xx2xx10^(-6)=2sqrt10xx10^(-2)A=sqrt4000" "mA` |
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