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If a circuit made up of a resistance 1 `Omega` and inductance 0.01 H, an alternating emf of 200 voit at 50 Hz is connected, then find the phase difference between the current and the emf in the circuit.A. `tan^(-1)(pi)`B. `tan^(-1)((pi)/(2))`C. `tan^(-1)((pi)/(4))`D. `tan^(-1)((pi)/(3))`

Answer» (a)`"tan"phi=((X_(L))/(R))` and `X_(L)=OmegaL=(2pifL)=(2pi)(50)(0.01)=piomega`
also `R=1Omegaimplies phi="tan"^(-1)(pi)`


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