1.

Calculate the maximum efficiency of an engine operating between `100^(@)C` and `25^(@)C`

Answer» Efficiency `=(T_(2)-T_(1))/(T_(2))`
`T_(2)=100+273=373K`
`T_(1)=25+273=298K`
Efficiency `=(373-298)/(373)`
`=(75)/(373)=0.20=20%`.


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