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Calculate the maximum efficiency of an engine operating between `100^(@)C` and `25^(@)C` |
Answer» Efficiency `=(T_(2)-T_(1))/(T_(2))` `T_(2)=100+273=373K` `T_(1)=25+273=298K` Efficiency `=(373-298)/(373)` `=(75)/(373)=0.20=20%`. |
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