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Calculate the mean deviatioin about median age for the age distribution of 100 persons given below: |
Answer» Solution :![]() Here `n=100impliesN/2=100/2=50` `:.` Median clas `=35.5-40.5` Now `l_(1)=35.5,l_(2)=40.5,C=37,F=26` Median `M=l_(1)+((N/2-C)(l_(2)-l_(1)))/f` `=35.5+((50-37)xx(40.5xx35.5))/26` `=35.5+2.5=38` Now mean deviation `=(sumf_(i)|x_(i)-M|)/(sumf_(i))=735/100` `=7.35` |
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