1.

Calculate the mean deviation of the following income groups of five and seven members from their medians:IIncome in ₹IIIncome in ₹400038004200400044004200460044004800460048005800

Answer»

Let us calculate the mean deviation for the first data set.

Since the data is arranged in ascending order,

4000, 4200, 4400, 4600, 4800

Median = 4400

Total observations = 5

We know that,

MD = 1/n ∑ni=1|di|

Where, |di| = |xi – M|

xi|di| = |xi – 4400|
4000400
4200200
44000
4600200
4800400
Total1200

MD = 1/n ∑ni=1|di|

= 1/5 × 1200

= 240

Let us calculate the mean deviation for the second data set.

Since the data is arranged in ascending order,

3800, 4000, 4200, 4400, 4600, 4800, 5800

Median = 4400

Total observations = 7

We know that,

MD = 1/n ∑ni=1|di|

Where, |di| = |xi – M|

xi|di| = |xi – 4400|
3800600
4000400
4200200
44000
4600200
4800400
58001400
Total3200

MD = 1/n ∑ni=1|di|

= 1/7 × 3200

= 457.14

∴ The Mean Deviation of set 1 is 240 and set 2 is 457.14



Discussion

No Comment Found

Related InterviewSolutions