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Calculate the mole fractions of the components of the solution composed by `92g` glycerol and `90g` water ? (M(water) = 18 , M (glycerol) = 92) . |
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Answer» Moles of water = 90 g /18 g = 5 mol water Moles of glycerol = 92g/92g = 1 mol glycerol Total moles in solution `= 5 + 1 = 6` mol Mole fraction of water = 5 mol/6 mol = 0.833 Mole fraction of glycerol = 1 mol/6mol = 0.167 |
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