1.

Calculate the mole fractions of the components of the solution composed by `92g` glycerol and `90g` water ? (M(water) = 18 , M (glycerol) = 92) .

Answer» Moles of water = 90 g /18 g = 5 mol water
Moles of glycerol = 92g/92g = 1 mol glycerol
Total moles in solution `= 5 + 1 = 6` mol
Mole fraction of water = 5 mol/6 mol = 0.833
Mole fraction of glycerol = 1 mol/6mol = 0.167


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