InterviewSolution
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InterviewSolution
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Calculate the moment of inertia of a. a ring of mass `M` and radius `R` about an axis coinciding with the diameter of the ring. b. as thin disc about an axis coinciding with the diameter. |
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Answer» Let `X` and `Y` axis be along two perpendicular diameters of the ring. BY symmetry`I_(x)=I_(y)` and by perpendicular axis theorem `I_(z)=I_(x)+I_(y)`. But we know that `I_(z)=MR^(2)` `MR^(2)=I_(x)+I_(y)^(z)=2I_(x)` `implies I_(x)=I_(y)=(MR^(2))/2` Situation of a thin disc (i.e. a circular plate) the moment of inertia about a diameter is `I=1/2(1/2MR^(2))=1/4MR^(2)` |
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