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Calculate the moment of inertia of a circular disc of radius `10 cm`, thickness `5 mm` and uniform density `8 g cm^(-3)`, about a transverse axis through the centre of the disc. |
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Answer» Here, `r = 10 cm, t = 5mm = 0.5 cm`, `rho = 8 g cm^(-3)` Mass of disc, `m = pi r^(2) xx r xx rho` `3.14 (10)^(2) xx 0.5 xx 8 = 1.256 xx 10^(3) gm` `I =(1)/(2)mr^(2) = (1)/(2) xx1.256 xx 10^(3) xx 10^(2)` `= 6.28 xx 10^(4) g cm^(2)` |
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