1.

Calculate the moment of inertia of a circular disc of radius `10 cm`, thickness `5 mm` and uniform density `8 g cm^(-3)`, about a transverse axis through the centre of the disc.

Answer» Here, `r = 10 cm, t = 5mm = 0.5 cm`,
`rho = 8 g cm^(-3)`
Mass of disc, `m = pi r^(2) xx r xx rho`
`3.14 (10)^(2) xx 0.5 xx 8 = 1.256 xx 10^(3) gm`
`I =(1)/(2)mr^(2) = (1)/(2) xx1.256 xx 10^(3) xx 10^(2)`
`= 6.28 xx 10^(4) g cm^(2)`


Discussion

No Comment Found

Related InterviewSolutions