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Calculate the mutual inductance between two coils when a current of 4A changing to 8A in 0.5s in one coil, induces an emf of 50 mV in the other coil. Data : I_(1) = 4 A, I_(2) = 8 A, dt = 0.5 s, e=50 mV = 50 xx 10^(-3) V, M = ? |
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Answer» Solution :`E=M.(dI)/(dt)` `:.M=-(e)/(((dI)/(dt)))= -(e)/(((I_(2)-I_(1))/(dt)))` ` = - (50 XX 10^(-3))/(((8-4)/(0.5)))= 6.25 xx 10^(-3)` `:.M= 6.025` MH |
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