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Calculate the mutual inductance between two coils when a current of 2A changes to 6A in 2 seconds and induces an emf of 20 mV in the secondary coil. |
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Answer» Solution :`|E| = M (dI)/(dt)` `20 xx 10^(-3) = M((6-2))/(2) " or " M = 10 mH` |
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