1.

Calculate the normality of `0.74 g Ca(OH)_(2)` in `10 mL` of solution.

Answer» Correct Answer - 2
`because "Eq.of"Ca(OH)_(2)=74//2`
and volume of solution `=10xx10^(-3)L`
`therefore "Normality"=(w)/(ExxV_(("in litre")))`
`=(0.74xx2)/(74xx10xx10^(-3))=2N`


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