Calculate the number of molecules present in 53g of Sodium Carbonate.

1.	Calculate the number of molecules present in 53g of Sodium Carbonate. Som
Answer» Avagadro's constant states that 1 mole of any substance has 6.022× 10²³ molecules/atoms. Find the number of moles of 53 g of Na2CO3:molar mass Na2CO3 = 23 × 2 + 12 + 16× 3 = (46+12+48) = 106 moles = mass/molar mass = 53/106 = 0.5 moles 1 mole = 6.022×10²³ atoms Then 0.5 moles = 6.022× 10²³× 0.5 atoms = 3.011× 10²³ atoms of Na2CO3

Calculate the number of molecules present in 53g of Sodium Carbonate. Som

Answer»

Avagadro's constant states that 1 mole of any substance has 6.022× 10²³ molecules/atoms.

Find the number of moles of 53 g of Na2CO3:molar mass Na2CO3 = 23 × 2 + 12 + 16× 3 = (46+12+48) = 106

moles = mass/molar mass = 53/106 = 0.5 moles

1 mole = 6.022×10²³ atoms Then 0.5 moles = 6.022× 10²³× 0.5 atoms = 3.011× 10²³ atoms of Na2CO3