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| 1. |
calculate the number of moleculesin each cubic metre of a gas at 1 atm and `27^(@)C`. |
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Answer» We have `pV=NkappaT` Or, `N=(pV)/(kappaT)` `=((1.0xx10^(5)Nm^(-2))(1 m^3))/((1.38xx10^(-23)JK^(-1))(300K)) ~~ 2.4xx10^(25).` |
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