1.

calculate the number of moleculesin each cubic metre of a gas at 1 atm and `27^(@)C`.

Answer» We have `pV=NkappaT`
Or, `N=(pV)/(kappaT)`
`=((1.0xx10^(5)Nm^(-2))(1 m^3))/((1.38xx10^(-23)JK^(-1))(300K))
~~ 2.4xx10^(25).`


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