Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 4000 H, the current changes from 5A to 7A and the flux changes from 760 to 800 Wb.(a) 100(b) 200(c) 300(d) 400I have been asked this question by my college professor while I was bunking the class.This is a very interesting question from Ferromagnetic Cored Inductor in a DC Circuit topic in division Inductance in a DC Circuit of Basic Electrical Engineering

Calculate the number of turns in an inductor with a ferromagnetic core

1.	Calculate the number of turns in an inductor with a ferromagnetic core when the inductance is 4000 H, the current changes from 5A to 7A and the flux changes from 760 to 800 Wb.(a) 100(b) 200(c) 300(d) 400I have been asked this question by my college professor while I was bunking the class.This is a very interesting question from Ferromagnetic Cored Inductor in a DC Circuit topic in division Inductance in a DC Circuit of Basic Electrical Engineering
Answer» Right CHOICE is (b) 200 Best explanation: From the formula of incremental inductance, we know that: L=(Change in flux/Change in CURRENT)*NUMBER of turns Substituting the values from the given question, we get N=200.

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