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Calculate the orbital period of the electron in the first excited state of hydrogen atom. |
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Answer» Solution :`becauser_(n) =( in_(0) n^(2) h^(2))/( PI m e^(2)) ` and`v_(n) = (e^(2))/(2 in_(0) n h)` <BR> `therefore `Orbital period `T_(n) =(2 pi r_(n))/(v_(n)) = (4 in_(0)^(2) n^(3) h^(3))/( me^(4))` In firstexcitedstate of hydrogenatom n = 2 . ,br>`therefore"" T_(n) = ( 4 xx (8.85 xx 10^(-12))^(2) xx (2)^(3) xx (6.63 xx 10^(-34))^(3))/((9.1 xx 10^(-31)) xx (1.6 xx 10^(-19))^(4)) = 3.14 xx 10^(-15) s` |
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