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Calculate the percentage of `BaO` in `29.0 g` mixture of `BaO` and `CaO` which just reacts with `100.8 mL` of `6.0M HCl`. |
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Answer» Let a g of `BaO` and b g of `CaO` are present. `:. a+b=29`….(i) Meq. of `BaO+Meq`. of `CaO=Meq`.of `HCl` `:. 56a+153b=2591`….(iii) By eq. (i) and (ii), `a=19.03 g, b=9.97 g` `:. %` of `BaO=(19.03)/(29)xx100= 65.62%` |
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