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Calculate the perimeter of a rectangle whose area is 25x^ 2 -35x+12.? |
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Answer» 25x²-35x+12=025x²-(20+15)X+12=025x²-20x-15x+12=05X(5x-4)-3(5x-4)=0(5x-3) (5x-4) =01. 5x-3 = 05x = 3x = 3/52. 5x-4 = 0 5x = 4 x = 4/5length = 4/5 , breadth = 3/5perimeter of rectangle= 2(l+b) = 2(4/5+3/5) = 2×7/5 = 14/5 |
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