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Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×10^8 m/s(in 10^-8 order)(a) 0.5(b) 72(c) 4(d) 36This question was posed to me during an interview for a job.The query is from Lossy and Lossless Dielectrics in chapter EM Wave Propagation of Electromagnetic Theory |
Answer» CORRECT answer is (c) 4 The best explanation: The phase constant is GIVEN by β = ω√(με), where ω is the FREQUENCY in rad/s and 1/√(με) is the velocity of WAVE. On substituting √(με) = 3×10^8 and ω = 12, we get β = 12/(3×10^8) = 4 x 10^-8m/s. |
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