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Calculate the potential energy of the system of charges shown in the figure. |
Answer» Solution : AC=BC=CD=DA=a `AC=BD=sqrt2.a` Potential energy of the system of CHARGES, `U=(1)/(4pi epsi_(0)) (SUM q_(1)q_(2))/(r)` `U=(1)/(4pi epsi_(0)) [q^(2)/a+(-q^(2))/(a)+(+q^(2))/(a)+(-q^(2))/(a)+(-q^(2))/(sqrt2.a)+(-q^(2))/(sqrt2.a)]=(1)/(4piepsi). (-2q^(2))/(sqrt2a)=(-sqrt2.q^(2))/(4pi epsi_(0)a)` |
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