1.

Calculate the power of lens of the spectacles necessary to rectify the defect of nearsightedeness fof a person who could see clearly onlyup to a distance of 1.8 m.

Answer»

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Solution :The maximumdistance the person COULD SEED is, x = 1.8 m
The lens should have a focallength of f = - x m = - 1.8 m
it is a concaveor diverging lens.
The POWER of the lens is, `P = (1)/(1.8m)` = 0.56 diopter


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