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Calculate the power of lens of the spectacles necessary to rectify the defect of nearsightedeness fof a person who could see clearly onlyup to a distance of 1.8 m. |
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Answer» <P> Solution :The maximumdistance the person COULD SEED is, x = 1.8 mThe lens should have a focallength of f = - x m = - 1.8 m it is a concaveor diverging lens. The POWER of the lens is, `P = (1)/(1.8m)` = 0.56 diopter |
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