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Calculate the pressure for `CO_(2)` at equilibrium if `DeltaG^(@)=31.1kcal` at `300 K` for `CaCO_(3(s))hArrCaO_((s))+CO_(2(g))` |
Answer» `CaCO_(3(g))hArrCaO_((s))+CO_(2(g))` `:. K_(p)=P_(CO_(2))` Also `-DeltaG^(@)=2.303RT log K_(p)` `-31.1xx10^(3)=2.303xx2xx300 log K_(p)` `:. K_(p)=P_(CO_(2))=3.11xx10^(-23)` |
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