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Calculate the propagation constant of a wave with impedance and admittance given by 32 and 12 respectively.(a) 19.6(b) 17.6(c) 15.6(d) 13.6This question was posed to me in a national level competition.I need to ask this question from Intrinsic Impedance and Propagation Constant topic in section Transmission Lines of Electromagnetic Theory

Answer»

The correct option is (a) 19.6

Best explanation: The propagation constant is given by γ = √(ZY), where Z is the IMPEDANCE and Y is the admittance. On SUBSTITUTING for Z = 32 and Y = 12,we GET γ = 19.6 UNITS.



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