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Calculate the quantity of electricity that would be required to reduce 12.3g of nitrobenzene to aniline, if current efficiency is 50% . If the potential drops across the cell is 3.0V, how much energy will be consumed ? |
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Answer» `C_(6)H_(5)NO_(2)+6H^(+)+6e rarrC_(6)H_(5)NH_(2)+2H_(2)O` `N^(3+)+6e rarr N^(3-)` `therefore` Eq. wt. of nitrobenzene `=(M)/(6)=(123)/(6)` Since current efficiency is 50% `therefore i=(50i_(0))/(100)` Now `w=("E.i.t")/(96500), 12.3=(123xxi_(0)xxtxx50)/(6xx100xx96500)` `therefore i_(0)xx t=115800` coulomb Now energy used `QxxV=115800xx3=347.4kJ` |
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