Saved Bookmarks
| 1. |
Calculate the radius of the earth if the density of the earth is equal to the density of the nucleus. [mass of earth 5.97xx10^(24)kg]. |
|
Answer» Solution :The density of the nucleus of an atom `rho_(N) = 2.3 xx 10^(17) kg m^(-3)` `rho_(N) = rho_(E) = 2.3 xx 10^(17) kg m^(-3)` Mass of the earth `M_(E) = 5.97 xx 10^(24)`kg Density of the earth, `rho_(E) = (m_(E))/(V)` ` = (m_(E))/(4/3 pi r^(3))` `r^(3) = (m_(E))/((4)/(3) pi rho_(E) ) = (5.97 xx 10^(24))/(1.33 xx 3.14 xx2.3 xx 10^(17))` ` = (5.97 xx 10^(24))/(9.60526 xx 10^(17))` `r^(3) = 0.6215 xx 10^(7) m^(3)` ` r = 183.85 m` `r APPROX 180 m`. |
|