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| 1. |
Calculate the radius of the third Bohr orbit of the hydrogen atom(h=6.625xx10^-34 Js epsilon^0=8.85xx10^-12 Fm^-1,e=1.6xx10^-19C,m=9.1xx10^-31kg) |
| Answer» SOLUTION :`R=n^2h^2epsilon^2/pime^2` here n=3 `therefore r= (3^2(6.625xx10^(-34))^2 xx(8.85xx10^(-32)))/(3.14xx(9.1xx10^(-31))xx(1.6xx10^(-19)))=4.78A^@` | |