1.

Calculate the ratio of electric and gravitational force between two protons. Charge of each proton is 1.6 xx 10^(-19)C,mass is 1.672 xx 10^(-27) kg and G = 6.67 xx 10^(-11) Nm^(-2)kg^(-2)?

Answer»

SOLUTION :`Q_1 = 1.6 xx 10^(-19) C, Q_2 = 1.6 xx 10^(-19) C`
r is the distance between the two protons
ELECTROSTATIC force between two protons
`F_1 = 9 xx 10^(9) (Q_1Q_2)/(r^2) m_1 = m_2 = 1.672 xx 10^(-27) kg`
`G = 6.67 xx 10^(-11) NM^(2)//kg^(2)`
Gravitational force between them
`F_2 = G(m_1 m_2)/(r^2) :. (F_1)/(F_2) = (9 xx 10^9 Q_1Q_2)/(G.m_1 m_2)`
`= (9 xx 10^(9) xx 1.6 xx 10^(-19) xx 1.6 xx 10^(-19))/(6.67 xx 10^(-11) xx 1.672 xx 10^(-27) xx 1.672 xx 10^(-27)) = 1.23 xx 10^(36)`


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