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| 1. |
Calculate the ratio of electric and gravitational force between two protons. Charge of each proton is 1.6 xx 10^(-19)C,mass is 1.672 xx 10^(-27) kg and G = 6.67 xx 10^(-11) Nm^(-2)kg^(-2)? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Q_1 = 1.6 xx 10^(-19) C, Q_2 = 1.6 xx 10^(-19) C` <br/> r is the distance between the two protons <br/> <a href="https://interviewquestions.tuteehub.com/tag/electrostatic-2069468" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTROSTATIC">ELECTROSTATIC</a> force between two protons <br/> `F_1 = 9 xx 10^(9) (Q_1Q_2)/(r^2) m_1 = m_2 = 1.672 xx 10^(-27) kg` <br/> `G = 6.67 xx 10^(-11) <a href="https://interviewquestions.tuteehub.com/tag/nm-579234" style="font-weight:bold;" target="_blank" title="Click to know more about NM">NM</a>^(2)//kg^(2)` <br/> Gravitational force between them <br/> `F_2 = G(m_1 m_2)/(r^2) :. (F_1)/(F_2) = (9 xx 10^9 Q_1Q_2)/(G.m_1 m_2)` <br/> `= (9 xx 10^(9) xx 1.6 xx 10^(-19) xx 1.6 xx 10^(-19))/(6.67 xx 10^(-11) xx 1.672 xx 10^(-27) xx 1.672 xx 10^(-27)) = 1.23 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/36-309156" style="font-weight:bold;" target="_blank" title="Click to know more about 36">36</a>)`</body></html> | |