Calculate the ratio of sine of incident angle to the sine of reflected angle when the refractive indices of medium 1 and 2 are given as 2.33 and 1.66 respectively.(a) 0.71(b) 1.4(c) 2(d) 3.99I had been asked this question in semester exam.Origin of the question is Snell Law and Critical Angle topic in division EM Wave Propagation of Electromagnetic Theory

Calculate the ratio of sine of incident angle to the sine of reflected

1.	Calculate the ratio of sine of incident angle to the sine of reflected angle when the refractive indices of medium 1 and 2 are given as 2.33 and 1.66 respectively.(a) 0.71(b) 1.4(c) 2(d) 3.99I had been asked this question in semester exam.Origin of the question is Snell Law and Critical Angle topic in division EM Wave Propagation of Electromagnetic Theory
Answer» Right choice is (a) 0.71 For EXPLANATION: The Snell law is given by N1 sin θi = N2 sin θt. To get sin θi/sin θt, the ratio is N2/N1. On substituting for N1 = 2.33 and N2 = 1.66, we get 1.66/2.33 = 0.71.

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