Calculate the ratio of the amount of heat energy lost during the conversion of 20 g of water at 0^(@)C to ice at 0^(@)C to heat energy gained during the conversion of same amount of water at 100^(@)C to steam at 100^(@)C.

Calculate the ratio of the amount of heat energy lost during the conve

1.	Calculate the ratio of the amount of heat energy lost during the conversion of 20 g of water at 0^(@)C to ice at 0^(@)C to heat energy gained during the conversion of same amount of water at 100^(@)C to steam at 100^(@)C.
Answer» Solution :Latent heat of fusion or FREEZING is 80 cal/g that is 1 g of ice requires80 cal 20 g ice requires ? = 20 + 80 = 1600 cal Latent heat of VAPOURISATION of WATER is 540 kg cal/gthat is 1 g water requires 540 cal 20 g water requires ? `20 xx 540` = 10800 cal `therefore` Ratio = 1600 : 10800 = 1 : 6.75