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Calculate the ratio of the frequencies of the radiation emitted due to transition of the electron in a hydrogen atom from its (i) second permitted energy level to the first level, and (ii) highest permitted energy level to the second permitted level. |
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Answer» Solution :We know that frequency of RADIATION emitted due to transition of an electron in a hydrogen atom from N state to n, stale is given by `v = (13.6 e)/(h) [(1)/(n_(J)^(2))-(1)/(n_(i)^(2))]` For 2-1 transition (i.e., `n_(i) = 2` and `n_(j) = 1`) we , have `V = (13.6e)/(h) [(1)/((1)^(2)) - (1)/((2)^(2))] = (3)/(4) xx (13.6e)/(h)"".......(i)` Forn - 2 transition(i.e., `n_(i) = oo ` and `n_(j) = 2`)we have . `v = (13.6e)/(h) [(1)/((2)^(2)) - (1)/((oo)^(2))] = (1)/(4) xx (13.6 e)/(h)` `rArr""(v)/(v)= (3)/(1)orv = 3 v` |
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