1.

Calculate the relative rates of diffusion for `.^(235)UF_(6)` and `.^(238)UF_(6)`.

Answer» Mol. Mass `.^(235)UF_(6) = 235 + 6 xx 19 = 349`
Mol. Mass `.^(238)UF_(6) = 238 + 6 xx 10 = 352`
`(r_(1))/(r_(2)) = sqrt((M_(2))/(M_(1))) = sqrt((352)/(349)) = 1.0043`
`r_(1) : r_(2) :: 1.0043 : 1.0000`


Discussion

No Comment Found

Related InterviewSolutions