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Calculate the relative rates of diffusion for `.^(235)UF_(6)` and `.^(238)UF_(6)`. |
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Answer» Mol. Mass `.^(235)UF_(6) = 235 + 6 xx 19 = 349` Mol. Mass `.^(238)UF_(6) = 238 + 6 xx 10 = 352` `(r_(1))/(r_(2)) = sqrt((M_(2))/(M_(1))) = sqrt((352)/(349)) = 1.0043` `r_(1) : r_(2) :: 1.0043 : 1.0000` |
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