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Find the temperature at which 3 moles of `SO_(2)` will occupy a volume of 10 litre at a pressure of 15 atm `a = 6.71 atm "litre"^(2) mol^(-2), b = 0.0564 " litre " mol^(-1)` |
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Answer» `(P + (an^(2))/(V^(2))) (V = nb) = nRT` `(15 + (6.71 xx 9)/(100)) (10 - 3 xx 0.0564) = 3 xx 0.082 xx T` `T = 624 K` |
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