1.

Calculate the resolving power of a telescope when light of wavelength `540 nm` is used. Diameter of objective lens is `6 cm`.A. `9.1 xx10^(-4)"rad"^(-1)`B. `0.1xx10^(-4)"rad"^(-1)`C. `5xx10^(-4)"rad"^(-1)`D. `6xx10^(-4)"rad"^(-1)`

Answer» Correct Answer - B
Given `D=6cm=6xx10^(-2)m`
`lambda=540nm=540xx10^(-9)m`
Resolving power of the telescope
`RP=(D)/(1.22lambda)=(6xx10^(-2))/(1.22xx540xx10^(-9))`
`=(6)/(122xx54)xx10^(8)` rad
In terms of `"rad"^(-1)`
`RP^(-1)=(1)/(RP)=(122xx54)/(6xx10^(8))"rad"^(-1)`
`=0.1 xx 10^(-4)"rad"^(-1)`


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