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Calculate the resolving power of a telescope when light of wavelength `540 nm` is used. Diameter of objective lens is `6 cm`.A. `9.1 xx10^(-4)"rad"^(-1)`B. `0.1xx10^(-4)"rad"^(-1)`C. `5xx10^(-4)"rad"^(-1)`D. `6xx10^(-4)"rad"^(-1)` |
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Answer» Correct Answer - B Given `D=6cm=6xx10^(-2)m` `lambda=540nm=540xx10^(-9)m` Resolving power of the telescope `RP=(D)/(1.22lambda)=(6xx10^(-2))/(1.22xx540xx10^(-9))` `=(6)/(122xx54)xx10^(8)` rad In terms of `"rad"^(-1)` `RP^(-1)=(1)/(RP)=(122xx54)/(6xx10^(8))"rad"^(-1)` `=0.1 xx 10^(-4)"rad"^(-1)` |
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