Calculate the resonance enegry of `N_(2)O` form the following data `Delta_(f)H^(Theta) of N_(2)O = 82 kJ mol^(-1)` Bond enegry of `N-=N, N=N, O=O,` and `N=O` bond is `946, 418, 498`, and `607 kJ mol^(-1)`, respectively.A. `-88KJmol^(-1)`B. `-44KJmol^(-1)`C. `-22KJmol^(-1)`D. None of these

Calculate the resonance enegry of `N_(2)O` form the following data `De

1.	Calculate the resonance enegry of `N_(2)O` form the following data `Delta_(f)H^(Theta) of N_(2)O = 82 kJ mol^(-1)` Bond enegry of `N-=N, N=N, O=O,` and `N=O` bond is `946, 418, 498`, and `607 kJ mol^(-1)`, respectively.A. `-88KJmol^(-1)`B. `-44KJmol^(-1)`C. `-22KJmol^(-1)`D. None of these
Answer» Correct Answer - A `N_(2)(g)+(1)/(2)O_(2)(g)rarrN_(2)O` `N-=N+(1)/(0)0=0rarrN=N=0` Calculated `DeltaH_(f)^(0)(N_(2)O)=[B.E._((N-=N))+(1)/(2)B.E.(0=0)]` `-[B.E._(N=N))+B.E._(N=0)]` `=[946+(498)/(2)]-[418+607]=+170KJ//mol` Resonance energy=observed `DeltaH_(f)^(0)` -calculated `DeltaH^(0)_(f)=82-170=-88KJmol^(-1)`

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Calculate the resonance enegry of `N_(2)O` form the following data `Delta_(f)H^(Theta) of N_(2)O = 82 kJ mol^(-1)` Bond enegry of `N-=N, N=N, O=O,` and `N=O` bond is `946, 418, 498`, and `607 kJ mol^(-1)`, respectively.A. `-88KJmol^(-1)`B. `-44KJmol^(-1)`C. `-22KJmol^(-1)`D. None of these

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