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Calculate the rms speed of Bra molecules at 23°C and 1.00 atm. What is1.50 atm?Q4.the rms speed of Br2 at 23°C and

Answer» <p>V(rms) = SQRT (3RT/M)</p><p>T = 25 C = 298 KM = 0.1598 kg/molR = 8.314 J/(mol⋅K)</p><p>V(rms) = SQRT(3*8.314*298/0.1598) = 216 m/s</p>


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