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Calculate the rms speed of smoke particles of mass `5 xx 10^(-17) kg` in their Brownian motion in air at NTP. Given `k_(B) = 1.38 xx 10^(-23) J//K` |
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Answer» Correct Answer - `1.5 cm//s` `C_(rms) = ? M = 5 xx 10^(-17) kg` `k_(B) = 1.38 xx 10^(-23) J//K T = 273 K` `C_(rms)sqrt((3kT)/(m)) = sqrt((3 xx 1.38 xx 10^(-23) xx 273)/(5 xx 10^(-17)))` `C_(rms) = sqrt((4.14 xx 273)/(5)) xx 10^(-2)m//s = 1.5 cm//s` |
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