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Calculate the shortest wavelength of the spectral lines emitted in Balmer series. [Given Rydberg constant R = 10^(7) m^(-1)]. |
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Answer» Solution : WAVELENGTHS of spectral lines of Balmer series are given by the relation: `(1)/(LAMBDA) = R [(1)/((2)^(2)) - (1)/(n^(2))] ` , where n = 3,4,5,……… . For shortest wavelength`n = oo`and it is given that`R = 10^(7) m^(-1)` `therefore""(1)/(lambda_("MIN")) = 10^(7) [(1)/((2)^(2)) - (1)/((oo)^(2))] =(1)/(4) xx 10^(7) RARR "" lambda_("min") = 4 xx 10^(-7) m` |
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