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Calculate the smallest angle resolved by a telescope with an objective of 5.0m diameter. What minimum magnification is needed to enable the human eye to utilize the resolution? (Aperture of the eye =2.5 mm, lambda= 5500 dotA). |
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Answer» Solution :Here, `lambda 5500 dotA= 5500xx 10^(-10)m` apertureof objective `a_(0) = 5.0m` Aperture of eye, `a_(a)= 2.5mm = 2.5xx 10^(-3)m` `triangle theta = 1.22(lambda)/(a)= 1.22((5500xx10^(-10)m)/(5M))= 1.34xx 10^(-7)RAD` Minimum MAGNIFICATION needed, `M_(0)= ("aperature of the objective "(a_0))/("aperature of the eye "(a_a))= (0.5m)/(2.5xx 10^(-3)m)=2000`. |
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