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Calculate the specific activites of Na^(24) and U^(235) nucliedes whose half-lifes are 15 hours and 7.1.10^(8) years respectively. |
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Answer» Solution :The specific acivity of `Na^(24)` is `lambda(N_(A))/(M)=(N_(A)In 2)/(MT_(1/2))= 3.22xx10^(17) dis//(gm.sec)` Here M= MOLAR weight of `N_(a)^(24)= 24 gm, N_(A)` is Avogadro NUMBER & `T(1/2)` is the half-life of `Na^(24)` SIMILARLY the soecific activity of `U^(235)` is `(6.023xx10^(23)xxIn 2)/(235xx10^(8)xx365xx86400)` `=0.793xx10^(5) dis(gm-s)` |
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