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Calculate the specific activities of Na^(24) and U^(235) nuclides whose half lives are 15 hrs and 7.1 xx 10^8 yrs : |
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Answer» `3.2 xx 10^(20), 7.9 xx 10^(7) Bq//kg` No. of atom in 1 kg of `NA^(24)=(6.03 xx 10^(26))/(24)` `A_(sod) ("activity of sodium")=lambda N` `=(0.6931)/(15 xx 3600) xx (6.03 x 10^(26))/(24)` `=3.2 xx 10^(20) Bq kg^(-1)` `A_("uran")=(0.6931)/(7.1 xx 10^(8) xx 365 xx 86400)=(6.03 xx 10^(26))/(235)` `=7.9 xx 10^(7) Bq kg^(-1)` |
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